JEE Main 2019 — Electrostatics Question with Solution
From: JEE Main 2019 (Online) 11th January Evening Slot
Question
An electric field of 1000 V/m is applied to an electric dipole at angle of 45o. The value of electric dipole moment is 10–29 C.m. What is the potential energy of the electric dipole?
Choose an option
Show full solutionCorrect option: A
Correct answer
A- 7 10–27 J
Step-by-step explanation
U =
= PE cos
= (1029) (103) cos 45o
= 0.707 1026 J
= 7 1027 J.
= PE cos
= (1029) (103) cos 45o
= 0.707 1026 J
= 7 1027 J.
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This is a previous-year question from JEE Main 2019, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.