JEE Main 2018 — Electrostatics Question with Solution
From: JEE Main 2018 (Online) 16th April Morning Slot
Question
Two identical conducting spheres A and B, carry equal charge. They are separated by a distance much larger than their diameters, and the force between theis F. A third identical conducting sphere, C, is uncharged. Sphere C is first touhed to A, then to B, and then removed. As a result, the force between A and B would be equal to :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
Let, change of A and B = q
Force between them, F =
When C touched with A then charge of A. Will fl;ow to C and divide into half parts.
charge of A and C ,
qA = qB =
Then C touched with B, then charge on B,
qB =
Force between A and B,
F' =
=
=
=
Force between them, F =
When C touched with A then charge of A. Will fl;ow to C and divide into half parts.
charge of A and C ,
qA = qB =
Then C touched with B, then charge on B,
qB =
Force between A and B,
F' =
=
=
=
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