JEE Main 2025PhysicsElectrostaticsElectric Potential Energy And Electric PotentialeasyMCQ

JEE Main 2025Electrostatics Question with Solution

From: JEE Main 2025 (Online) 2nd April Evening Shift

Question

Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is V . The potential difference between the points A and (shown in the figure) is :JEE Main 2025 (Online) 2nd April Evening Shift Physics - Electrostatics Question 9 English

This question includes a diagram. The text above accompanies the figure.

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Show full solutionCorrect option: D
Correct answer
D

Step-by-step explanation

JEE Main 2025 (Online) 2nd April Evening Shift Physics - Electrostatics Question 9 English Explanation

Step 1: Formula for Potential Difference
The potential difference () between two points in a uniform electric field is found by multiplying the electric field () by the distance () between the points:

Step 2: Find the Electric Field
The total potential difference between the two plates is , and they are 10 cm apart. So, the electric field between the plates is: Here, distance is in centimeters.

Step 3: Calculate Potential Difference Between A and B
Points A and B are 4 cm apart. So, the potential difference between A and B will be:

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About this question

This is a previous-year question from JEE Main 2025, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.