JEE Main 2016 — Electrostatics Question with Solution
From: JEE Main 2016 (Online) 10th April Morning Slot
Question
Within a spherical charge distribution of charge density (r), N equipotential surfaces of potential V0, V0 + V, V0 + 2V, .......... V0 + NV ( V > 0), are drawn and have increasing radii r0, r1, r2,..........rN, respectively. If the difference in the radii of the surfaces is constant for all values of V0 and V then :
Choose an option
Show full solutionCorrect option: C
Correct answer
C (r)
Step-by-step explanation
Here, v and r are same for any pair of surface.
we know,
Electric field, E =
E = constant [As dv and dr are constant]
Electric field inside the spherical charge distribution.
E =
Now, as E = constant
r = constant
(r)
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