JEE Main 2019 — Electrostatics Question with Solution
From: JEE Main 2019 (Online) 10th April Morning Slot
Question
A uniformly charged ring of radius 3a and total
charge q is placed in xy-plane centred at origin.
A point charge q is moving towards the ring
along the z-axis and has speed u at z = 4a. The
minimum value of u such that it crosses the
origin is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Ui + Ki = Uf + Kf
v =
v =
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This is a previous-year question from JEE Main 2019, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.