JEE Main 2017PhysicsElectrostaticsMediumMCQ

JEE Main 2017 — Electrostatics Question with Solution

JEE Main 2017 (08 Apr Online)

Question

There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at P, in the region, is found to vary between the limits 589.0 V to  589.8 V. What is the potential at a point on the sphere whose radius vector makes an angle of 60° with the direction of the field?

Choose an option

Show full solutionCorrect option: D
Correct answer
D589.6 V

Step-by-step explanation



ΔV=Ed

Along diameter  ∆V=589.8-589.0  V
                              =0.8 V

0.8=Ed

Now

ΔV=E d 2 cosθ=0.4×cos 60 o

=0.2

∴589.8−V=0.2

V=589.6 V

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About this question

This is a previous-year question from JEE Main 2017, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.