JEE Main 2019 — Electrostatics Question with Solution
From: JEE Main 2019 (Online) 9th January Evening Slot
Question
Two point charges q1 and q2( 25 C) are placed on the x-axis at x = 1 m and x = 4 m respectively. The electric field (in V/m) at a point y = 3 m on y-axis is,
[take = 9 109 Nm2C2]
[take = 9 109 Nm2C2]
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Electric field due to charge :
E1 sin1 + E1 cos1
Where,
E1
sin 1
and cos1 =
Electric field due to 25 C charge,
E2 sin2 E2 cos2
where
E2
V/m
sin2 =
and cos2 =
Net electric field,
= +
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