JEE Main 2021PhysicsElectrostaticsElectric Flux And Gauss LawmediumNumerical

JEE Main 2021Electrostatics Question with Solution

From: JEE Main 2021 (Online) 24th February Evening Shift

Question

A point charge of +12C is at a distance 6 cm vertically above the centre of a square of side 12 cm as shown in figure. The magnitude of the electric flux through the square will be __________ 103 Nm2/C.

JEE Main 2021 (Online) 24th February Evening Shift Physics - Electrostatics Question 160 English

This question includes a diagram. The text above accompanies the figure.

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Show full solutionCorrect answer: 226
Correct answer
226

Step-by-step explanation

Given, charge, q = 12 C = 12 106C

Height of charge from surface, h = 6 cm = 6 102 m and side of square, a = 12 cm = 12 102 m

Using Gauss law, it is a part of cube of side 12 cm and charge at centre so;

Nm2 / C

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About this question

This is a previous-year question from JEE Main 2021, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.