JEE Main 2019PhysicsElectrostaticsElectric Potential Energy And Electric PotentialmediumMCQ

JEE Main 2019Electrostatics Question with Solution

From: JEE Main 2019 (Online) 12th January Morning Slot

Question

There is a uniform spherically symmetric surface charge density at a distance R0 from the origin. The charge distribution is initially at rest and starts expanding because of mutual repulsion. The figure that represents best the speed V (R(t)) of the distribution as a function of its instantaneous radius R (t) is :

Choose an option

Show full solutionCorrect option: B
Correct answer
BJEE Main 2019 (Online) 12th January Morning Slot Physics - Electrostatics Question 195 English Option 2

Step-by-step explanation

At any instant 't'

Total energy of charge distribution is constant

i.e.     

  

  V =

  V = = C

Also the slope of v-s curve will go on decreasing

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About this question

This is a previous-year question from JEE Main 2019, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.