JEE Main 2015 — Electrostatics Question with Solution

By the property of electrostatic shielding in the conductors $E=0$ in the conductor. So, electric flux,$=0$ through a dotted Gaussian surface as shown



The net enclosed charge through the Gaussian surface$=0$,$\Rightarrow$ The net charge $Q_1$ on the inner surface$=0$, but the equal and opposite induced charge on the surface will be distributed non uniformly on the inner surface

So, ${\sigma }_1=0$

$\because Q_1=0$ on the inner surface

So, net charge $Q_2=0$ on the outer surface as conductor is neutral but $\because$ outer surface is free from any electric field so no charge density exists on the outer surface. So, ${\sigma }_2=0$ .