JEE Main 2016PhysicsElectrostaticsHardMCQ

JEE Main 2016 — Electrostatics Question with Solution

JEE Main 2016 (10 Apr Online)

Question

Within a spherical charge distribution of charge density ρr,  N equipotential surfaces of potential V0, V0+∆V, V0+2∆V,…V0+N∆V ∆V>0, are drawn and have increasing radii r0, r1, r2,…rN, respectively. If the difference in the radii of the surfaces is constant for all values of V0 and ∆V then :

Choose an option

Show full solutionCorrect option: C
Correct answer
C ρ( r ) ∝  1 r

Step-by-step explanation

E=− ΔV Δr

∴    △v and △r are constant

E = constant

E=Kqr2=c

⇒   q ∝r2

∴   q=∫0rρ4πr2dr 

⇒   ρ∝1r

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About this question

This is a previous-year question from JEE Main 2016, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.