JEE Main 2022PhysicsElectrostaticsMediumMCQ

JEE Main 2022Electrostatics Question with Solution

JEE Main 2022 (26 Jun Shift 2)

Question

Sixty four conducting drops each of radius 0.02 m and each carrying a charge of 5 μC are combined to form a bigger drop. The ratio of surface density of bigger drop to the smaller drop will be

Choose an option

Show full solutionCorrect option: B
Correct answer
B4:1

Step-by-step explanation

Total volume will be constant. Therefore, n4π3r3=4π3R36413r=RR=4r

Final surface charge density σ'=nσ04πr24πR2=64×σ0r216r2σ'σ0=41

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Electrostatics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.