JEE Main 2022PhysicsElectrostaticsElectric Charges And Coulombs LawmediumMCQ

JEE Main 2022Electrostatics Question with Solution

From: JEE Main 2022 (Online) 24th June Evening Shift

Question

Two identical charged particles each having a mass 10 g and charge 2.0 107C are placed on a horizontal table with a separation of L between them such that they stay in limited equilibrium. If the coefficient of friction between each particle and the table is 0.25, find the value of L. [Use g = 10 ms2]

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Show full solutionCorrect option: A
Correct answer
A12 cm

Step-by-step explanation

According to given information:

= mg

Putting the values, we get

L = 12 cm

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About this question

This is a previous-year question from JEE Main 2022, covering the Electrostatics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.