JEE Main 2017 — Electromagnetic Waves Question with Solution
From: JEE Main 2017 (Online) 8th April Morning Slot
Question
Magnetic field in a plane electromagnetic wave is given by
= B0 sin (k x + t)
Expression for corresponding electric field will be :
Where c is speed of light.
= B0 sin (k x + t)
Expression for corresponding electric field will be :
Where c is speed of light.
Choose an option
Show full solutionCorrect option: A
Correct answer
A = B0 c sin (k x + t) V/m
Step-by-step explanation
The relation between electric and magnetic field is ,
C =
= C
Electric field component is perpendicular to the direction of magnetic field. Given magnetic field is along y axis,
So, electric field along z axis will be
= B0 C sin (kx + t) v/m
C =
= C
Electric field component is perpendicular to the direction of magnetic field. Given magnetic field is along y axis,
So, electric field along z axis will be
= B0 C sin (kx + t) v/m
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This is a previous-year question from JEE Main 2017, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.