JEE Main 2020 — Electromagnetic Waves Question with Solution
From: JEE Main 2020 (Online) 7th January Morning Slot
Question
If the magnetic field in a plane electromagnetic wave is given by
= 3 10-8 sin(1.6 103x + 48 1010t) T, then what will be expression for electric field ?
= 3 10-8 sin(1.6 103x + 48 1010t) T, then what will be expression for electric field ?
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Show full solutionCorrect option: A
Correct answer
A = (9sin(1.6 103x + 48 1010t) V/m)
Step-by-step explanation
Given = 3 10-8 sin(1.6 103x + 48 1010t) T
We know,
E0 = (3 10-8) (3 10-8) = 9 V/m
= (9sin(1.6 103x + 48 1010t) V/m)
We know,
E0 = (3 10-8) (3 10-8) = 9 V/m
= (9sin(1.6 103x + 48 1010t) V/m)
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This is a previous-year question from JEE Main 2020, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.