JEE Main 2020 — Electromagnetic Waves Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
A plane electromagnetic wave, has
frequency of 2.0 1010 Hz and its energy density is 1.02 10–8 J/m3 in vacuum. The amplitude of the magnetic field of the wave is close to
( and speed of light
= 3 108 ms–1)
frequency of 2.0 1010 Hz and its energy density is 1.02 10–8 J/m3 in vacuum. The amplitude of the magnetic field of the wave is close to
( and speed of light
= 3 108 ms–1)
Choose an option
Show full solutionCorrect option: C
Correct answer
C160 nT
Step-by-step explanation
Energy density,
1.02 10–8 =
Also, c =
= 1.02 10–8 2
= 1.02 10–8 2
B0 = 16 10-8 T = 160 nT
1.02 10–8 =
Also, c =
= 1.02 10–8 2
= 1.02 10–8 2
B0 = 16 10-8 T = 160 nT
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Electromagnetic Waves chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.