JEE Main 2019 — Electromagnetic Waves Question with Solution
From: JEE Main 2019 (Online) 8th April Evening Slot
Question
The magnetic field of an electromagnetic wave
is given by :-
The associated electric field will be :-
The associated electric field will be :-
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
If we use that direction of light propagation will be along . Then (A) option is
correct.
Magnitude of E = CB
E = 3 × 108 × 1.6 × 10–6 ×
E = 4.8 ×
and are perpendicular to each other
Either direction of or from given option
Also wave propagation direction is parallel to which is
is along ()
Magnitude of E = CB
E = 3 × 108 × 1.6 × 10–6 ×
E = 4.8 ×
and are perpendicular to each other
Either direction of or from given option
Also wave propagation direction is parallel to which is
is along ()
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This is a previous-year question from JEE Main 2019, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.