JEE Main 2017PhysicsElectromagnetic WavesHardMCQ

JEE Main 2017 — Electromagnetic Waves Question with Solution

JEE Main 2017 (02 Apr)

Question

An electron beam is accelerated by a potential difference V to hit a metallic target to produce X-rays. It produces continuous as well as characteristic X-rays. If λmin is the smallest possible wavelength of X-ray in the spectrum, the variation of logλmin with logV is correctly represented in :

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Show full solutionCorrect option: B
Correct answer
B

Step-by-step explanation

K.E.=eV,

KE=The kinetic energy of electron

The maximum energy of photon=K.E.

eV=hCλmin

⇒λmin V=hCe=constant

Taken log in both sides

lnλmin+lnV=lnconstant

⇒lnλmin=-lnV+ln(constant)

y=-ax+c the straight line of negative slope.

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About this question

This is a previous-year question from JEE Main 2017, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.