JEE Main 2018PhysicsElectromagnetic WavesMediumMCQ

JEE Main 2018 — Electromagnetic Waves Question with Solution

JEE Main 2018 (15 Apr)

Question

A monochromatic beam of light has a frequency v=32π×1012 Hz and is propagating along the direction i^+j^ 2 . It is polarized along the k^ direction. The acceptance form the magnetic field is:

Choose an option

Show full solutionCorrect option: C
Correct answer
C E0Ci^-j^2 Cos⁡104i^+j^2.r→+3×1012t

Step-by-step explanation

E^×B^ should have given direction of wave propagation,⇒  K^×B^∥ i^+j^ 2 
 K^×i^+j^ 2=j^--i^2=i^+j^ 2 ∥i^+j^ 2  . 

Wave propagation vector K^ should be along i^+j^ 2.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Electromagnetic Waves chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2018, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.