JEE Main 2023PhysicsElectromagnetic WavesEasyMCQ

JEE Main 2023 — Electromagnetic Waves Question with Solution

JEE Main 2023 (11 Apr Shift 2)

Question

A plane electromagnetic wave of frequency 20 MHz propagates in free space along x-direction. At a particular space and time E→=6.6j ^ V m-1. What is B→ at this point?

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Show full solutionCorrect option: A
Correct answer
A2.2×10-8k^T

Step-by-step explanation

It is given that 

 E→=6.6j^( V m-1).

The relation between the electric, magnetic field and speed of light is E→×B→=c→.

Clearly,   B→=B0(k^)

Using the relation,
     cB0=E
⇒B0=Ec=6.63×108=2.2×10-8 T

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About this question

This is a previous-year question from JEE Main 2023, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.