JEE Main 2014PhysicsElectromagnetic WavesMediumMCQ

JEE Main 2014 — Electromagnetic Waves Question with Solution

JEE Main 2014 (06 Apr)

Question

During the propagation of electromagnetic wave in a particular medium :-

Choose an option

Show full solutionCorrect option: C
Correct answer
CElectric energy density is equal to the magnetic energy density

Step-by-step explanation

UVelec=12∈0E2      ....(i)

UVmag=12B2/μ0     ....(ii)

B = E C  (for EMW)         ....(iii)

and C= 1 μ 0 ε 0 .....(iv)

∴ devide eqn (i) by (ii) 

(U/V)elec(U/V)mag=12ε0E212B2/μ0

= ( E B ) 2 μ 0 ε 0

by using eq (iii) & (iv)

= C 2 C 2 =1

⇒(U/V)elec.=(UV)mag

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About this question

This is a previous-year question from JEE Main 2014, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.