JEE Main 2020PhysicsElectromagnetic WavesEasyMCQ

JEE Main 2020 — Electromagnetic Waves Question with Solution

JEE Main 2020 (08 Jan Shift 2)

Question

A plane electromagnetic wave of frequency 25GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic filed is given by B→=5×10-8 j^ T. The corresponding electric field E→ is (speed of light =3×108 m s-1 )

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Show full solutionCorrect option: D
Correct answer
D15i^ Vm

Step-by-step explanation

Given, the electromagnetic wave is propagating in z i.e., +k^ direction.

The relation between the magnitudes of electric field, magnetic field and the speed of light is given by

EB=C

⇒ E=B×C
⇒ E=5×10-8×3×108=15 V m-1

We know that the direction of propagation of electromagnetic wave is along E→×B→.

So, E→=15 i^ V m-1

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About this question

This is a previous-year question from JEE Main 2020, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.