JEE Main 2019PhysicsElectromagnetic WavesEasyMCQ

JEE Main 2019 — Electromagnetic Waves Question with Solution

JEE Main 2019 (10 Jan Shift 1)

Question

If the magnetic field of a plane electromagnetic wave is given by (The speed of light =3×108 m/s)

B=100×10-6sin⁡2π×2×1015t-xc then the maximum electric field associated with it is:

Choose an option

Show full solutionCorrect option: A
Correct answer
A3×104 N C-1

Step-by-step explanation

We know that relation between electric field E and magnetic field B is given by:

EB=c⇒E=Bc=100×10-6×3×108 V m-1=3×104 V m-1

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About this question

This is a previous-year question from JEE Main 2019, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.