JEE Main 2019PhysicsElectromagnetic WavesMediumMCQ

JEE Main 2019 — Electromagnetic Waves Question with Solution

JEE Main 2019 (10 Apr Shift 1)

Question

The electric field of a plane electromagnetic wave is given by
E→=E0i^cos⁡kzcos⁡(ωt)
The corresponding magnetic field B→ is then given by:

Choose an option

Show full solutionCorrect option: C
Correct answer
CB→=E0Cj^sin⁡kzsin(ωt)

Step-by-step explanation

E→=E0 i^ cos kz cosωt
E→=E02 i^ cos kz-ωt+E02i^ coskz+ωt
B→=E02C j^ cos kz-ωt+E02Cj^ coskz+ωt
=E02Cj^ 2 sin kzsinωt
=E0Cj^  sin kzsinωt

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About this question

This is a previous-year question from JEE Main 2019, covering the Electromagnetic Waves chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.