JEE Main 2020 — Electromagnetic Induction Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
A circular coil of radius 10 cm is placed in a
uniform magnetic field of 3.0 10–5 T with its
plane perpendicular to the field initially. It is
rotated at constant angular speed about an
axis along the diameter of coil and
perpendicular to magnetic field so that it
undergoes half of rotation in 0.2 s. The
maximum value of EMF induced (in V) in the
coil will be close to the integer _______.
Enter your answer
Show full solutionCorrect answer: 15
Correct answer
15
Step-by-step explanation
At any time
flux = BA cos
|emf| = = BA sin
|emf|max = BA = BA
=
= 15 10-6
= 15 V
|emf| = = BA sin
|emf|max = BA = BA
=
= 15 10-6
= 15 V
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Electromagnetic Induction chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.