JEE Main 2015PhysicsElectromagnetic InductionEasyMCQ

JEE Main 2015 — Electromagnetic Induction Question with Solution

JEE Main 2015 (10 Apr Online)

Question

When the current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self-inductance of the coil is

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Show full solutionCorrect option: A
Correct answer
A 1.67 H

Step-by-step explanation

Magnetic flux

ϕ=LI ⇒ ∆ϕ∆t=L ∆I∆t

∴ εindaverage= ∆ϕ∆t=L ∆I∆t

⇒ 50=L × 5-20.1

⇒  53=L

⇒   L=1.67 H

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About this question

This is a previous-year question from JEE Main 2015, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.