JEE Main 2020PhysicsElectromagnetic InductionMediumNumerical

JEE Main 2020Electromagnetic Induction Question with Solution

JEE Main 2020 (02 Sep Shift 1)

Question

A circular coil of radius 10 cm is placed in a uniform magnetic field of 3.0×10-5 T with its plane perpendicular to the field initially. It is rotated at constant angular speed about an axis along the diameter of coil and perpendicular to magnetic field so that it undergoes half of rotation in 0.2 s. The maximum value of EMF induced (in μV) in the coil will be close to the integer....

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Show full solutionCorrect answer: 15
Correct answer
15

Step-by-step explanation

Flux as a function of time ϕ=B·A=ABcos(ωt)

Emf induced,

e=-dϕdt=ABωsin(ωt)

Max. value of Emf = ABω

=πR2Bω

=3.14×0.1×0.1×3×10-5×π0.2=15

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About this question

This is a previous-year question from JEE Main 2020, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.