JEE Main 2021PhysicsElectromagnetic InductionMotional Emf And Eddy CurrentmediumMCQ
JEE Main 2021 — Electromagnetic Induction Question with Solution
From: JEE Main 2021 (Online) 20th July Morning Shift
Question
The arm PQ of a rectangular conductor is moving from x = 0 to x = 2b outwards and then inwards from x = 2b to x = 0 as shown in the figure. A uniform magnetic field perpendicular to the plane is acting from x = 0 to x = b. Identify the graph showing the variation of different quantities with distance.
This question includes a diagram. The text above accompanies the figure.
Choose an option
▸Show full solutionCorrect option: B
Correct answer
BA-Flux, B-EMF, C-Power dissipated
Step-by-step explanation
As the rectangular conductor moves in field area, so flux is increasing up to x = b, then flux is generated on return journey from x = b to x = 0. The flux is shown by plot A of the graph.
As, emf, e=−dtdϕ, which is shown by curve B and power dissipated, P = VI which is shown by curve C.
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