JEE Main 2025 — Electromagnetic Induction Question with Solution
JEE Main 2025 (28 Jan Shift 2)
Question
A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time with a constant velocity. If the induced EMF is , then value of n is _.
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Correct answer
1
Step-by-step explanation
As the bar moves without change in orientation, the length of bar will be proportional to its distance from the vertex.
i.e.
$\begin{aligned}
& \text { induced emf } E=B / v \\
& =c B v^2 t
\end{aligned}$
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This is a previous-year question from JEE Main 2025, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.