JEE Main 2021PhysicsElectromagnetic InductionEasyNumerical

JEE Main 2021 — Electromagnetic Induction Question with Solution

JEE Main 2021 (26 Aug Shift 2)

Question

A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s-1 in a uniform horizontal magnetic field of 3.0×10-2 T. The maximum emf induced in the coil will be _______×10-2 volt (rounded off to the nearest integer).

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Show full solutionCorrect answer: 60
Correct answer
60

Step-by-step explanation

Emf=BωNAsinωt

Emfmax=BωNA=BωNπR2

=3×10-2×50×20×π×64104≈60×10-2 V

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About this question

This is a previous-year question from JEE Main 2021, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.