JEE Main 2016 — Electromagnetic Induction Question with Solution
From: JEE Main 2016 (Online) 10th April Morning Slot
Question
A conducting metal circular-wire-loop of radius r is placed perpendicular to a
magnetic field which varies with time as
B = B0e , where B0 and are constants, at time t = 0. If the resistance of the loop is R then the heat generated in the loop after a long time (t ) is :
B = B0e , where B0 and are constants, at time t = 0. If the resistance of the loop is R then the heat generated in the loop after a long time (t ) is :
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
Given,
B = B0e
Area of the circular loop, A = r2
Flux = BA = r2 B0 e
Induced emf in the loop,
= = r2B0e
Heat generated
=
=
=
=
=
=
B = B0e
Area of the circular loop, A = r2
Flux = BA = r2 B0 e
Induced emf in the loop,
= = r2B0e
Heat generated
=
=
=
=
=
=
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This is a previous-year question from JEE Main 2016, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.