JEE Main 2019 — Electromagnetic Induction Question with Solution
From: JEE Main 2019 (Online) 12th April Morning Slot
Question
The figure shows a square loop L of side 5 cm which is connected to a network of resistances. The whole setup is moving towards right with a constant speed of 1 cm s-1. At some instant, a part of L is in a uniform
magnetic field of 1 T, perpendicular to the plane of the loop. If the resistance of L is 1.7 , the current in the
loop at that instant will be close to :


This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: B
Correct answer
B170 A
Step-by-step explanation
Since it is a balanced wheatstone bridge, its equivalent resistance =
So total resistance
So total resistance
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Electromagnetic Induction chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2019, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.