JEE Main 2019 — Electromagnetic Induction Question with Solution
From: JEE Main 2019 (Online) 8th April Morning Slot
Question
A 20 Henry inductor coil is connected to a
10 ohm resistance in series as shown in figure.
The time at which rate of dissipation of energy
(joule's heat) across resistance is equal to the
rate at which magnetic energy is stored in the
inductor is :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
PR = i2 × R
PB = V × i
PL = Vi – i2R
Vi – i2R = i2R
t = ln(2) =
PB = V × i
PL = Vi – i2R
Vi – i2R = i2R
t = ln(2) =
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