JEE Main 2021PhysicsElectromagnetic InductionMediumMCQ

JEE Main 2021Electromagnetic Induction Question with Solution

JEE Main 2021 (16 Mar Shift 1)

Question

A conducting bar of length L is free to slide on two parallel conducting rails as shown in the figure

Two resistors R1 and R2 are connected across the ends of the rails. There is a uniform magnetic field B pointing into the page. An external agent pulls the bar to the left at a constant speed v.

The correct statement about the directions of induced currents I1 and I2 flowing through R1 and R2 respectively is :

Choose an option

Show full solutionCorrect option: C
Correct answer
CI1 is in clockwise direction and I2 is in anticlockwise direction

Step-by-step explanation

Given, the external agent pulls the bar towards left. According to Lenz's law and Fleming's right hand rule, there will be a motional EMF generated in the bar. The right-hand rule tells us that the magnetic force on positive charges will be in downward direction and the electric equivalent circuit can be drawn as shown below.

So, I1 is in the clockwise direction and I2 is in the anticlockwise direction.

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About this question

This is a previous-year question from JEE Main 2021, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.