JEE Main 2018 — Electromagnetic Induction Question with Solution
JEE Main 2018 (15 Apr Shift 1 Online)
Question
An ideal capacitor of capacitance is charged to a potential difference of . The charging battery is then disconnected. The capacitor is then connected to an ideal inductor of self inductance . The current at a time when the potential difference across the capacitor is , is:
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Given: Capacitance,
Inductance
Current = ?
Using energy conservation
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This is a previous-year question from JEE Main 2018, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.