JEE Main 2022PhysicsElectromagnetic InductionMediumMCQ

JEE Main 2022 — Electromagnetic Induction Question with Solution

JEE Main 2022 (26 Jul Shift 1)

Question

In a series LR circuit XL=R and power factor of the circuit is P1. When capacitor with capacitance C such that XL=XC is put in series, the power factor becomes P2. The ratio P1P2 is

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Show full solutionCorrect option: B
Correct answer
B12

Step-by-step explanation

In case of L-R circuit

Z=XL2+R2 Therefore, power factor

P1=cosϕ=RZ

As XL=R ⇒Z=2R

⇒P1=R2R⇒P1=12

In case of  L-C-R circuit

Z=R2+XL-XC2

According to the question XL=XC ⇒Z=R  ⇒P2=cosϕ=RR=1

⇒P1P2=12

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About this question

This is a previous-year question from JEE Main 2022, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.