JEE Main 2022PhysicsElectromagnetic InductionEasyMCQ

JEE Main 2022 — Electromagnetic Induction Question with Solution

JEE Main 2022 (26 Jun Shift 2)

Question

A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s-1. If the horizontal component of earth's magnetic field is 0.2×10-4 T, then emf induced between the two ends of the conductor is

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Show full solutionCorrect option: B
Correct answer
B50μV

Step-by-step explanation

Given here,  BH=0.2×10-4 T, ω=5 rad s-1 and l= 1 m.

Emf induced in a rotating conducting rod is given by,

ε=12Bωl2

Substituting the given values, we obtain

ε=12×0.2×10-4×5×12=0.5×10-4 V=50 μV

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About this question

This is a previous-year question from JEE Main 2022, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.