JEE Main 2023PhysicsElectromagnetic InductionHardMCQ

JEE Main 2023 — Electromagnetic Induction Question with Solution

JEE Main 2023 (24 Jan Shift 2)

Question

A metallic rod of length L is rotated with an angular speed of ω normal to a uniform magnetic field B about an axis passing through one end of rod as shown in figure. The induced emf will be :

.

Choose an option

Show full solutionCorrect option: C
Correct answer
C12BL2ω

Step-by-step explanation

Linear velocity at the distance x from the centre can be written as, v=ωx.

Therefore, induced EMF due to small element will be,

dε=Bvdx=Bωxdx

Integrating both sides, we get

∫dε=∫Bωxdx

⇒ε=Bω∫0Lxdx=BωL22

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About this question

This is a previous-year question from JEE Main 2023, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.