JEE Main 2023PhysicsElectromagnetic InductionEasyMCQ

JEE Main 2023 — Electromagnetic Induction Question with Solution

JEE Main 2023 (08 Apr Shift 2)

Question

An emf of 0.08 V is induced in a metal rod of length 10 cm held normal to a uniform magnetic field of 0.4 T, when move with a velocity of:

Choose an option

Show full solutionCorrect option: D
Correct answer
D2 m s-1

Step-by-step explanation

The formula to calculate the motional emf induced in a moving conductor in a magnetic field is given by

ε=Blv   ...1

Substitute the values of the known parameters into equation (1) and solve to calculate the required velocity of the rod.

0.08 V=0.4 T×10 cm×1 m100 cm×v⇒v=0.08 V0.4 T×10 cm×1 m100 cm= 2 m s-1

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About this question

This is a previous-year question from JEE Main 2023, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.