JEE Main 2021PhysicsElectromagnetic InductionMediumMCQ

JEE Main 2021 — Electromagnetic Induction Question with Solution

JEE Main 2021 (01 Sep Shift 2)

Question

A square loop of side 20 cm and resistance 1 Ω is moved towards right with a constant speed v0. The right arm of the loop is in a uniform magnetic field of 5 T. The field is perpendicular to the plane of the loop and is going into it. The loop is connected to a network of resistors each of value 4Ω. What should be the value of v0 so that a steady current of 2 mA flows in the loop ?

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Show full solutionCorrect option: C
Correct answer
C1 cm s-1

Step-by-step explanation

The EMF is induced in the coil when it is moving in a uniform magnetic field,
e=Bvl and the current, i=eR⇒BlvR=0.002 A
 ⇒v=0.002×RBl=0.002×4+15×0.2=0.01 m s-1=1 cm s-1.

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About this question

This is a previous-year question from JEE Main 2021, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.