JEE Main 2018PhysicsElectromagnetic InductionEasyMCQ

JEE Main 2018 — Electromagnetic Induction Question with Solution

JEE Main 2018 (16 Apr Online)

Question

A coil of cross-sectional area A having n turns is placed in a uniform magnetic field B. When it is rotated with an angular velocity ω, the maximum e.m.f. induced in the coil will be:

Choose an option

Show full solutionCorrect option: C
Correct answer
CnBAω

Step-by-step explanation

Magnetic flux through a coil of area A of n turns at an angle θ to the magnetic field of magnitude B is, φ=nBA cosθ=nBAcosωt. The induced emf,

ε=dϕdt=nBAωsin⁡ωt. Since, the maximum value of the sine function is 1,

εmax=nBAω

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About this question

This is a previous-year question from JEE Main 2018, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.