JEE Main 2023PhysicsElectromagnetic InductionHardNumerical

JEE Main 2023 — Electromagnetic Induction Question with Solution

JEE Main 2023 (30 Jan Shift 2)

Question

In an ac generator, a rectangular coil of 100 turns each having area 14×10–2 m2 is rotated at 360 rev min-1 about an axis perpendicular to a uniform magnetic field of magnitude 3.0 T. The maximum value of the emf produced will be ______ V.

[Take π=227]

Enter your answer

Show full solutionCorrect answer: 1584
Correct answer
1584

Step-by-step explanation

Maximum value of induced EMF can be written as,

ξmax=NABω

=100×14×10-2×3×360×2π60

=1584 V

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About this question

This is a previous-year question from JEE Main 2023, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.