JEE Main 2021PhysicsCurrent ElectricityCombination Of ResistancesmediumNumerical

JEE Main 2021Current Electricity Question with Solution

From: JEE Main 2021 (Online) 18th March Morning Shift

Question

The voltage across the 10 resistor in the given circuit is x volt.

JEE Main 2021 (Online) 18th March Morning Shift Physics - Current Electricity Question 200 English
The value of 'x' to the nearest integer is _________.

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Show full solutionCorrect answer: 7
Correct answer
7

Step-by-step explanation

JEE Main 2021 (Online) 18th March Morning Shift Physics - Current Electricity Question 200 English Explanation 1




JEE Main 2021 (Online) 18th March Morning Shift Physics - Current Electricity Question 200 English Explanation 2



JEE Main 2021 (Online) 18th March Morning Shift Physics - Current Electricity Question 200 English Explanation 3



I = 7A

Potential Across 10 resister

V10 = IR = 7 10 = 70V

V10 = 70V

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About this question

This is a previous-year question from JEE Main 2021, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.