JEE Main 2020 — Current Electricity Question with Solution
From: JEE Main 2020 (Online) 5th September Evening Slot
Question
In the circuit, given in the figure currents in
different branches and value of one resistor are
shown. Then potential at point B with respect to
the point A is :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: C
Correct answer
C+1 V
Step-by-step explanation
Let us assume the potential at A = VA = 0
Now at junction C, According to KCL
i1 + i3 = i2
1 A + i3 = 2 A
i3 = 1 A
Now Analyse potential along ACDB,
VA + 1 + i3(2) – 2 = VB
0 + 1 + 1(2) – 2 = VB
VB = 3 – 2 = 1 V
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Current Electricity chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.