JEE Main 2020 — Current Electricity Question with Solution
From: JEE Main 2020 (Online) 8th January Evening Slot
Question
A galvanometer having a coil resistance
100 gives a full scale deflection when a
current of 1 mA is passed through it. What is
the value of the resistance which can convert
this galvanometer into a voltmeter giving full
scale deflection for a potential difference of
10 V?
Choose an option
Show full solutionCorrect option: C
Correct answer
C9.9 k
Step-by-step explanation
ig = 1 mA , Rg = 100
V = ig(R + Rg)
10 = 1 × 10–3 (R + 100)
R = 9.9 k
V = ig(R + Rg)
10 = 1 × 10–3 (R + 100)
R = 9.9 k
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This is a previous-year question from JEE Main 2020, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.