JEE Main 2017 — Current Electricity Question with Solution
From: JEE Main 2017 (Online) 9th April Morning Slot
Question
A uniform wire of length 1 and radius r has a resistance of 100 . It is recast into a wire of radius The resistance of new wire will be :
Choose an option
Show full solutionCorrect option: A
Correct answer
A1600
Step-by-step explanation
Resistance of a wire of length l and radius r is given
by
R = =
R
Given, R1 = 100 , r1 = r, r2 = , R2 = ?
R2 = R1 = 16R1 = 1600
R = =
R
Given, R1 = 100 , r1 = r, r2 = , R2 = ?
R2 = R1 = 16R1 = 1600
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Current Electricity chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2017, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.