JEE Main 2019 — Current Electricity Question with Solution
From: JEE Main 2019 (Online) 9th January Morning Slot
Question
A resistance is shown in the figure. Its value and tolerance are given respectively by :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: B
Correct answer
B27 k, 10 %
Step-by-step explanation
From color code table :
For Red value is 2
For Violet value is 7
For Orange multiplier is 103
For Silver tolarence is 10%
Resistance and tolerance is
= 27 103 10%
= 27 k 10%
For Red value is 2
For Violet value is 7
For Orange multiplier is 103
For Silver tolarence is 10%
Resistance and tolerance is
= 27 103 10%
= 27 k 10%
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Current Electricity chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2019, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.