JEE Main 2019 — Current Electricity Question with Solution
From: JEE Main 2019 (Online) 12th January Evening Slot
Question
In the given circuit diagram, the currents, I1 = – 0.3 A, I4 = 0.8 A and I5 = 0.4 A, are flowing as shown. The currents I2, I3 and I6, respectively, are :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: D
Correct answer
D1.1 A, 0.4 A, 0.4 A
Step-by-step explanation
From KCL, I3 = 0.8 0.4 = 0.4A
I2 = 0.4 + 0.4 + 0.3
= 1.1 A
I6 = 0.4A
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Current Electricity chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2019, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.