JEE Main 2019 — Current Electricity Question with Solution
From: JEE Main 2019 (Online) 8th April Morning Slot
Question
A 200 resistor has a certain color code. If one
replaces the red color by green in the code, the
new resistance will be :
Choose an option
Show full solutionCorrect option: A
Correct answer
A500
Step-by-step explanation
200 = Red + Black + Brown
Green = 5
So, Green + Black + Brown = 500
Green = 5
So, Green + Black + Brown = 500
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This is a previous-year question from JEE Main 2019, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.