JEE Main 2019 — Current Electricity Question with Solution
From: JEE Main 2019 (Online) 9th April Evening Slot
Question
The resistance of a galvanometer is 50 ohm and
the maximum current which can be passed
through it is 0.002 A. What resistance must be
connected to it in order to convert it into an
ammeter of range 0 – 0.5 A ?
Choose an option
Show full solutionCorrect option: B
Correct answer
B0.2 ohm
Step-by-step explanation
We have
Ig Rg = (0.5 – Ig) S
(0.002) (50) = (0.5 – Ig) S
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This is a previous-year question from JEE Main 2019, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.